NCERT Solutions For Class 8 Maths Chapter 4 Data Handling

NCERT Solutions For Class 8 Maths Chapter 4 Data Handling Introduction

The information collected in the form of numbers in the context of a situation under study is called data.

For example :

Marks obtained by the students of your class in the monthly test in English, weights of students of your class, etc.

We systematically organise the data and then interpret it.

Sometimes, we represent the data graphically to get a clear idea of what it represents.

Question 1. A pictograph

It is a pictorial representation of data using symbols

Read and Learn More NCERT Solutions For Class 8 Maths

1. How many cars were produced in July?
Solution:

250 cars were produced in July

2. In which month was the maximum number of cars produced?
Solution:

The maximum number (= 400) was produced in September’

Question 2. A bar graph

It is a display of information using bars of uniform width, with equal gaps in between. Their heights are proportional to the respective values.

1. What is the information given by the bar graph?
2. In which year is the increase in the number of students maximum?
3. In which year is the number of students maximum?
4. Slate whether true or false :

‘The number of students during 2005-2006 is twice that of 2003-04’.

Solution:

1. The bar graph gives information about the number of students in class VIII in various academic years in the school.

2. Increase in the number of students in

2004 – 05 = 200 – 100 = 100

Increase in the number of students in

2005- 06 = 250 – 200 = 50

Increase in the number of students in

2006-07 = 300 – 250 = 50

Increase in the number of students in

2007-08 = 350 – 300 = 50

Hence, the increase in the number of X students is maximum in the year 2004-2005.

3. The number of students is maximum in the year 2007-08.

4. The number of students during

2005-06 = 250

The number of students during

2003-04 = 100

Twice the number of students during

2003-04 = 2 xl00 = 200* 250

( = The number of students during 2005- 06)

Since the number of students during 2005-06 is not twice that of 2003-04, therefore the given statement is false.

Question 3. Double bar graph

Bar graph allowing Iwo sola of data simultaneously. It is useful for the comparison of the data.

1. What is the information given by the double bar graph?
2. In which subject has the performance improved the most?
3. In which subject has the performance deteriorated?
4. In which subject is the performance at par?

Solution:

1. The double bar graph gives information about the marks obtained by a student in different subjects in the academic years 2005-06 and 2006-07.

2. The performance has improved the most in the subject of Mathematics.

3. The performance has deteriorated in the subject of English.

4. The performance is at par in the subject of Hindi

Question 4. If we change the position of any of the bars of a bar graph, would it change the information being conveyed? Why
Solution:

No, because bar heights give the quantity for each category. Since by changing the position of any of the bars of a bar graph, the height of the bar remains unchanged, the information conveyed regarding the quantity remains unchanged

Question 5. Draw an appropriate graph to represent the given information.

Solution:

Question 6.

Solution:

Question 7. Percentage wins in ODI by 8 top cricket teams

Solution:

Circle Graph Or Pie Chart

A circle graph shows the relationship between a whole and its parts. We divide the whole circle into various sectors. The size of each sector is proportional to the information or activity it represents.

Question 8. Each of the following pie charts gives you a different piece of information about your class. Find the fraction ofthe circle representing each of these information

Solution:

1. Fraction ofthe circle representing the ‘girls’

= \(\frac{\text { Percentage of girls }}{\text { Percentage of all students }}\)

= \(\frac{50}{100}=\frac{1}{2}\)

Dividing the numerator and denominator by 50 [= HCF (50, 100)]

Fraction of the circle representing the boys

= \(\frac{\text { Percentage of boys }}{\text { Percentage of all students }}\)

= \(\frac{50}{100}=\frac{1}{2}\)

2. Fraction of the circle representing walk

= \(\frac{\text { Percentage of walk }}{\text { Total percentage of transport }} \)

= \(\frac{40}{100}=\frac{2}{5}\)

Dividing the numerator and denominator by 20 [= HCF (40, 100)]

Fraction ofthe circle representing‘cycle’

= \(\frac{\text { Percentage of cycle }}{\text { Total percentage of transport }} \)

= \(\frac{20}{100}=\frac{1}{5}\)

Fraction of the circle representing (Bus or car)

= \(\frac{\text { Percentage of Bus or } \mathrm{Car}}{\text { Total percentage of transport }}\)

= \(\frac{40}{100}=\frac{2}{5}\)

Dividing the numerator and denominator by 20 [= HCF (40, 100)]

3. The fraction of the circle represents those who hate Mathematic

= \(\frac{\text { Percentage of students who hate Mathematics }}{\text { Percentage of all students }}\)

= \(\frac{15}{100}=\frac{3}{20}\)

Dividing the numerator and denominator by 20

[= HCF (40, 100)]

Dividing the numerator and denominator by 5

[= HCF (15, 100)

The fraction ofthe circle representing those who whose Mathematic

= \(\frac{\begin{array}{c}
\text { Percentage of those who love Mathematics } \\
\end{array}}{\text { Percentage of all students }}\)

= \(\frac{100-15}{100}\)

= \(\frac{85}{100}=\frac{17}{20}\)

Question 9. Answer the following questions based on the pie chart given

1. Which type of programmes are viewed the most?
2. Which two types of programmes have several viewers equal to those watching sports channels

Solution:

From the given pie chart, we prepare the following table

1. Since the percentage of entertainment viewers is the highest, therefore, entertainment programmes are viewed the most.

2. Percentage of viewers watching the news

= 15% r

Percentage of viewers watching X informative = 10%

∴ Some of the percentages of viewers watching news and informative

= (15 + 10)% = 25%

= Percentage of viewers watching spo ts

Hence, news and information programmes have many viewers equal m those watching sports channels.

Drawing Pie Charts

The total angle at the centre of a circle is 360°. The central angles of sectors are fractions of 360°.

The central angle of a sector

= \(\left(\frac{\text { Value of the component represented by the sector }}{\text { Sum of the values of all the components }} \times 360^{\circ}\right)\)

Question 1. Draw a pie chart of the data given below. The time spent, by a child during a day.

1. Sleep – 8 hours
2. School – 6 hours
3. Homework – 4 hours
4. Play – 4 hours
5. Others – 2 hours

Solution:

Now, we make the pie chart pie chart

NCERT Solutions For Class 8 Maths Chapter 4 Data Handling  Exercise 4.1

Question 1. A survey was made to find the type of music Il\al a certain group of young people liked in a city. The adjoining pie chart shows the findings of this survey

1. From this pie chart answer the following
2. If 20 people liked classical music, how many young people were surveyed?
3. Which type of music is liked by the maximum number of people?
4. If a cassette company were to make 1000 CD’s, how many of each type would they make?

Solution:

1. Suppose that x young people were surveyed. Then, the number of young people who liked classical music = 10% of x

= \(\frac{10}{100} \times x=\frac{x}{10}\)

According to the question

⇒ \(\frac{x}{10}=20\)

x = 20 × 10

Multiplying both sides by 10

X = 200

Hence 200 young people were surveyed

2. Since the percentage of young people who liked light music is the highest, therefore, light music is liked by the maximum number of people

3. Total number of CD’s = 1000

Number of CD’s of semi-classical music

= 20% of 1000

= \(\frac{20}{100} \times 1000\)

= 200

Number of CDs of classical music 10% of 1000

= \(\frac{10}{100} \times 1000\)

=100

Number of CD’s of folk music

= 30% of 1000

= \(\frac{30}{100} \times 1000\)

= 300

Number of CDs of light music

= 40% of 1000

= \(\frac{40}{100} \times 1000\)

= 400

Question 2. A group of 360 people were asked to vote for their favourite season from the h “ee Semi seasons rainy, winter and summer.

1. Which season got the most votes?
2. Find the central angle ofeach sector.
3. Draw a pie chart to show this information.

Solution:

1. Since the no. of votes corresponding to the winter season is the maximum, therefore, winter season got the most votes.

2. Total votes = 90+ 120+ 150 = 360.

The central angle of the sector corresponds to the summer season

= \(\frac{\begin{array}{c}\text { Number of people who vote for summer season } \\\end{array}}{\text { Total number of people }} \times 360^{\circ} \)

= \(\frac{90}{360} \times 360^{\circ}=90^{\circ}\)

The central angle of the sector corresponds to the rainy season

= \(\frac{\begin{array}{c}\text { Number of people who vote for rainy season } \\\end{array}}{\text { Total number of people }} \times 360^{\circ}\)

= \(\frac{120}{360} \times 360^{\circ}=120^{\circ}\)

The central angle of the sector corresponding to the winter season

= \(\frac{\begin{array}{c}\text { Number of people who vote for winter season } \\\end{array}}{\text { Total number of people }} \times 360^{\circ}\)

= \(\frac{150}{360} \times 360^{\circ}=150^{\circ}\)

Pie Chart

Question 3. Draw a pie chart showing the following information. The table shows the colours Preferred  by a group of people

Find the proportion of each sector. For example,

Blue is – \(\frac{18}{36}=\frac{1}{2}\)

Green – \(\frac{9}{36}=\frac{1}{4}\)  and so on

Use this to find the corresponding and

Solution:

Pie chart:

Question 4. The adjoining pie chart gives the marks scored in an examination by students in Hindi, English, Mathematics, SocialScienceand Science. If the total marks obtained by the students were 540, answer the following questions:

1. In which subject did the student score 105 marks?

Hint: For 540 marks, the central angle

= 360°. So, for 105 marks, what is the central angle?

2. How many more malts were obtained by the student in Mathematics than in Hindi?

3. Examine whether the sum of the marks obtained in Social Science and Mathematics is more than that in Science and Hindi

Solution:

1. Total marks = 540

∴ Central angle corresponding to 540 marks

= 360°

∴  Central angle corresponding to 105 marks

= \(\frac{360^{\circ}}{540} \times 105=70^{\circ}\)

Since the sector having a central angle of 70° corresponds to Hindi, therefore, the student scored 105 marks in Hindi.

2. Central angle corresponding to the sector of mathematics = 90°

∴ Marks obtained by the student in Mathematics

= \(\frac{90^{\circ}}{360^{\circ}} \times 540\)

= 135

Marks obtained by the student in Hind =105

Hence, the student obtained 135 – 105 = 30 marks more in Mathematics than in Hindi.

3. Sum ofthe Central Angles for Social

Science and Mathematics

= 65° + 90° = 155°

Some of the central angles for Science and Hindi

= 80° + 70° = 150°

Since the sum of the central angles for Social Science and Mathematics is greater than the sum of the central angles for Science and Hindi, therefore the sum of the marks obtained in social science and mathematics is more than that in Science and Hindi.

Question 5.The number of students in a hostel, speaking different languages is given below. Display the data in a pie chart

Solution:

Now, we make the pie chart.

Chance And Probability

We face many situations where we take a chance and it does not go as per our wish. For example, on tossing a coin, we may get a head or we may get a tail; but simply by chance. There exist many situations when the chances of a certain thing happening or not happening are not equal.

Getting A Result

A random experiment is one whose outcome cannot be predicted exactly in advance.

Question 1. If you try to start a scooter, what arc the possible outcomes?
Solution:

If we try to start, a scooter, then the possible outcomes are

1. The scooter may start ;
2. The scooter may not start.

Question 2. When a die is thrown, what are the six possible outcomes?
Solution:

When a die is thrown, the six possible outcomes are 1, 2, 3, 4, 5 and 6.

Question 3. When you spin the wheel shown, what are the possible outcomes?  List them. (Outcome here means the sector at which the pointer stops).

Solution:

Since in the given wheel, there are three sectors A, B, and C, so, when we spin the wheel, the possible outcomes are A, B and C.

Question 4. You have a bag with five identical balls of different colours and you are to pull out (draw) a ball without looking at it; list the outcomes you would
Solution:

Since the given bag contains five identical balls of different colours, W, R, B, G and Y, therefore, when we pull out (draw) a ball without looking at it, the possible outcomes are W, R, B, G and Y.

Question 5. In throwing a die

1. Does the first player have a greater chance of getting a six?
Solution: No

2. Would the player who played after him have a lesser chance of getting a six?
Solution: No

3. Suppose the second player got a six. Does it mean that the third player would not have a chance of getting a six?
Solution: No

Equally Likely Outcomes

Outcomes of an experiment are equally likely if each has the same chance of occurring.

Linking Chances To Probability

Chances of the happening of an event lead us to find the probability of that event. Of course, we have to take into account the total number of chances related to a particular event under consideration

Coin And Die

Question 1. What is the probability of getting a tail?
Solution: The probability of getting a tail is \(\frac{1}{2}\)

Question 2. What is the probability of getting Ike number 5?
Solution: The probability of getting the number 5 is \(\frac{1}{6}\)

Question 3. What is the probability of getting the number 7?
Solution: The probability of getting the number 7 is 0.

Question 4. What is the probability of getting a number 1 through 6?
Solution: The probability of getting a number 1 through 6 is \(\frac{1}{6}\)

Probability of an event =\(\frac{\text { Number of outcomes that make an event }}{\text { Total number of outcomes of the experiment }} \text {, }\) when the outcomes are equally likely.

Outcomes As Events

One or more outcomes of an experiment make an event

Question 1. List the number of outcomes of getting a green sector and not getting a green sector on this wheel

1. Find the probability of getting a green sector.
2. Find the probability of not getting a green sector.

Solution:

1. Number of outcomes getting a green sector on this wheel = 5

The number of outcomes of not getting a green sector on this wheel = 3

2. Total number of equally likely outcomes = 8

Number of outcomes getting a green sector = 5

∴ Probability of getting a green sector

= \(=\frac{\begin{array}{l}
\text { Number of outcomes of getting a green sector } \\
\end{array}}{\text { Total number of outcomes }}\)

= \(\frac{5}{8}\)

Total number of equally likely outcomes = 8

Number of outcomes of not getting a green sector = 3

The probability of not getting a green sector

= \(\frac{\begin{array}{l}\text { Number of outcomes of getting a green sector }\end{array}}{\text { Total number of outcomes }}\)

= \(\frac{3}{8}\)

Chance And Probability Related To Real Life

Chances and probability are related to real life. The UHO of probability i.s ma(te in various cases in real life. For example, during elections ‘an exit poll’ is taken which gives a rough idea of the chance of winning of each candidate and predictions regarding the poll are made based on it. Here, we have used a small part of the group to find the characteristics of a large group.

NCERT Solutions For Class 8 Maths Chapter 4 Data Handling Exercise 4.2

Question 1. List the outcomes you can see in these experiments.

1. Spinning wheel

2. Tossing two coins together

Solution:

1. The outcomes we can see in spinning the given wheel are A, B, C and D.
2. The outcomes we can see in tossing two coins together are HT, HH, TH, and TT (HereIT means Head on first coin and Tail on the end coin and so on).

Question 2. When a die is thrown, list the outcomes of an event of getting

1.

1. A prime number
2. Not a prime number.

2.

1. A number greater than 5
2. A number not greater than 5

Solution:

Possible outcomes are :

1, 2, 3, 4, 5, and 6.

Out of these, prime numbers are 2, 3 and 5.

The outcomes of an event of getting a prime number are :

2, 3 and 5

The outcomes of an event of not getting a prime number are 1, 4 and 6.

The outcome of an event of getting a number greater than 5 is 6.

Outcomes of an event of getting a number not greater than 5 are1, 2, 3, 4 and 5

Question 3. Find the

1. The probability of the pointer stopping on D in
2. Probability of getting an AE from a well-shuffled deck of 52 playing cards?
3.  Probability of getting a red apple.

Solution:

1. There are 5 sectors on the spinning wheel represented by A, A, B, C and D. The pointer stopping on D has m only 1 outcome, i.e., D

∴ Probability of the pointer

Stopping on D =\(\frac{1}{5}\)

2. Total number of playing cards = 52

Number of possible outcomes = 52

Number of aces in a deck of playing cards = 4

∴Probability y of getting an ace from a well-shuffled deck of 52 playing cards =\(\frac{4}{52}\)

= \(\frac{1}{3}\)

3. Total number of apples = 7

Number of red apples = 4

The probability of getting a red apple

= \(\frac{4}{7}\)

Question 4. Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well One slip is chosen from the box without looking into it. What is the probability of this?

1. Getting a number 6?
2. Getting a number less than 6?
3. Getting a number greater than 6?
4. Getting a 1-digit number?

Solution:

Total number of outcomes of the event (1, 2. 3, 4, 5, 6, 7, 8, 9 and 10) = 10

1. Number of outcomes of getting a number 6 = 1

∴ The probability of getting the number 6

= \(\frac{1}{10}\)

2. There are 5 numbers (1, 2, 3, 4 and 5) less than 6.

∴  Number of outcomes getting a number less than 6 = 5

∴  Probability of getting a number Less than

6 = \(\frac{5}{10}\)

= \(\frac{1}{2}\)

3. There are ‘I number (7, 8, 9nnd 10) greater than

Number of outcomes of ting a number greater than G = 4

The probability of getting a number greater than 6 = 4 is greater than

6 = \(\frac{4}{10}\)

= \(\frac{2}{5}\)

There are 9 1-digit numbers(1, 2, 3, 4, 5, 6, 7, 8 and 9)

∴  Number of outcomes of getting a1-digit number = 9

∴  Probability of getting a 1-digit number = \(\frac{9}{10}\)

Question 5. If you have a spinning wheel with 3 green sectors, 1 blue sector and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a non-blue sector?
Solution:

Number of green sectors = 3

Number of blue sectors = 1

Number of red sectors = 1

∴  Total number of sectors

= 3+1+1 = 5

∴ Total number of outcomes of the event = 5

Number of outcomes of getting green sector = 3

Probability of getting a green sector

= \(\frac{3}{5}\)

Number of outcomes of getting non-blue sector

= Number of green sectors + Number of red sectors

= 3+1 = 4

∴ The probability of getting a non-blue

= \(\frac{4}{5}\)

Question 6 Find the probabilities ofthe (rents I have given in
Solution:

Total number of outcomes of the event (1. 2. 3, 4, 5 and 6) = 6

1.

1. Number of prime numbers

(2. 3 and 5) = 3

Number of outcomes of getting a prime number = 3

∴ Probability of getting a prime number

= \(\frac{3}{6}\)

= \(\frac{1}{2}\)

2. Number of non-prime numbers (1, 4 and 6) = 3

Number of outcomes of getting a prime number = 3

∴ Probability of gelling a non-prime

= \(\frac{3}{6}\)

= \(\frac{1}{2}\)

2.

1. Number greater than 5 = 6, i.e., only one.

∴ The probability of getting a number greater than 5 =\(\frac{1}{6}\)

2. Number of numbers not greater than 5 (1, 2, 3, 4 and 5) = 5

The number of outcomes of getting a number not greater than 5 = 5

Probability of getting a number not greater than 5 = \(\frac{5}{6}\)

NCERT Solutions For Class 8 Maths Chapter 4 Data Handling Multiple Choice Questions

Observe the following bar graph and answer the following questions :

Question 1. On which item has the maximum expenditure been done?

1. Conveyance
2. Rent
3. Fee
4. Servant’s salary.

Solution:  1. Conveyance

The height of the bar corresponding to conveyance is the maximum.

Question 2. On which item has the minimum expenditure been done?

1. Servant’s salary
2. Food
3. Rent
4. Conveyance.

Solution: 1. Servant’s salary

The height of the bar corresponding to the servant’s salary is the minimum.

Question 3. What is the expenditure on food?

1. ₹ 1000
2. ₹ 2000
3.  ₹3000
4.  ₹5000

Solution: 4. ₹5000

Expenditure done on food = 5 × 1000 = 5000.

Question 4. What is the difference between expenditures done on conveyance and rent?

1.  ₹ 1000
2.  ₹ 2000
3.  ₹ 3000
4.  ₹ 4000

Solution: 2. ₹ 2000

Expenditure done on conveyance

= 6 × 1000 = ₹ 6000

Expenditure done on rent = 4 × 1000

= ₹ 4000

.-. Difference = ₹ 6000 – ₹ 4000

= ₹ 2000

Question 5. ₹ 5000 is the expenditure done on

1. Rent
2. Food
3. Fee
4. Recreation

Solution: 2. Food

⇒ \(\frac{5000}{1000}\) = 5 cm is the height of the bar corresponding to food

Question 6. ₹60000 is the expenditure done on

1. Fee
2. Rent
3. Conveyance
4. Food

Solution:  3. Conveyance

⇒ \(\frac{6000}{1000}\) = 6 cm is the height of the bar corresponding to conveyance

Question 7. How much expenditure h;m been done in all?

1. 21000
2. 18000
3. 15000
4. 20000

Solution: 1. 21000

Total expenditure

= (1 + 6 + 4+ 5 + 2 + 3) × 1000

= ₹ 21000

Observe the following paragraph and answer the following questions:

Question 8. Of which subject are there the maximum books?

1. Hindi
2. English
3. Maths
4. Science

Solution: 1. Hindi

The height of the bar corresponding to Hindi is maximum.

Question 9. How many books are there on ofthe subject whose books are maximum?

1. 100
2. 200
3. 300
4. 400

Solution: 4.  400

Hindi  → 400

Question 10. Of which subject are there the minimum books?

1. Social
2. Science
3. Hindi
4. English

Solution: 1. Social

The height of the bar corresponding to Social Science is the minimum

Question 11. How many books are there on the subject whose books are minimum?

1. 100
2. 200
3. 30
4. 400

Solution: 1. 100

Social Science →  100

Question 12. Which two subjects have the same number of books?

1. Maths and Hindi
2. Hindi and English
3. English and Science
4. Science and Social Science

Solution: 3. English and Science

English → 200

Science → 200

Question 13. 300 books on the subject

1. Maths
2. English
3. Hindi
4. Science

Solution:  1. Maths

300 → Maths

Question 14. The difference of the number of books in English and Science is

1. 200
2. 100
3. 400
4. 0

Solution: 4. 0

200-200 = 0

Question 15. The difference of the number of books of Hindi and Social Science is

1. 200
2. 300
3. 400
4. 100

Solution: 2. 300

400-100 = 300

Question 16. The total number of books is

1. 1200
2. 1400
3. 1600
4. 1800

Solution: 1. 1200

300+400 + 200 + 200+ 100 = 1200

Question 17. The total number of books of English and Science is

1. 200
2. 100
3. 400
4. 0

Solution: 3. 400

200 + 200 = 400

Observe the pie chart given below and answer the following questions:

Question 18. The central angle for sector A is

1. 108°
2. 144°
3. 72°
4. 150°

Solution: 1. 108°

Central angle for sector A

= \(\frac{30}{100} \times 360^{\circ}\)

= 108°

Question 19. The central angle for sector B is

1. 108°
2. 144°
3. 72°
4. 150°

Solution: 2. 144°

Central angle for sector A

= \(\frac{40}{100} \times 360^{\circ}\)

= 144°

Question 20. Which sector has the greatest angle?

1. A
2. B
3. C
4. None of these

Solution: 2. B

Greatest percentage = 40% → B

Question 21. What is the difference between the central angles for Sector B and Sector C?

1. 36°
2. 72
3. 9°
4. 81°

Solution: 1. 36°

144° – 108° = 36°

Observe the pie chart and answer the English following questions

Question 22. Which two colours have the same central angles?

1. Red, yellow
2. Red, green
3. Yellow, green
4. Blue, red.

Solution:  1. Red, yellow

Red →  45% ; Yellow → 45%.

Question 23. Which colour has the greatest central angle?

1. Red
2. Yellow
3. Green
4. Blue

Solution: 4. Blue

Blue →  180°

Question 24. The proportion of the sector in red is

1. \(\frac{1}{2}\)
2. \(\frac{1}{4}\)
3. \(\frac{1}{8}\)
4. \(\frac{1}{3}\)

Solution: 3. \(\frac{1}{8}\)

⇒ \(\frac{45^{\circ}}{360^{\circ}}=\frac{1}{8}\)

Question 25. The difference between the central angles for green and blue is

1. 45°
2. 90°
3. 180°
4. 22 \(\frac{1}{2}\)

Solution: 2. 90°

Central angle for blue = 180°

Central angle for green = 90°

Difference = 180° – 90° = 90°.

Question 26. A child has a block in the shape of a cube with one letter written on each face as shown below

The cube is thrown once. What is the probability of getting A

1. \(\frac{1}{3}\)
2. \(\frac{1}{6}\)
3. \(\frac{1}{2}\)
4. \(\frac{1}{4}\)

Solution:  1. \(\frac{1}{3}\)

Probability =\(\frac{2}{6}\)

= \(\frac{1}{3}\)

Question 27. A die is thrown. What is the probability of getting an even prime number

1. \(\frac{1}{6}\)
2. \(\frac{1}{4}\)
3. \(\frac{1}{3}\)
4. \(\frac{1}{2}\)

Solution: 1. \(\frac{1}{6}\)

Even prime number = 2

Probability =\(\frac{1}{6}\)

NCERT Solutions For Class 8 Maths Chapter 4 Data HandlingTrue Or False

1. In the n chart, a whole circle is divided into various sectors – True

2. The number of times a particular observation that occurs in a given data is called its frequency – True

3. The probability of a sure event is 0– False

4. The probability of an impossible event is 1 – False

5. In a throw of a die, the outcomes are equally likely – True

NCERT Solutions For Class 8 Maths Chapter 4 Data Handling Fill In The Blanks

1. The difference between the highest and the lowest values ofthe observations in a data is called the Range of the data.

2. A geometric representation showing the relationship between a whole and its parts is called a → Pie chart

3. The probability that it will rain tomorrow is 0. 75. What is the probability that it will not rain tomorrow  → 0.25

4. Find the range ofthe marks obtained by 10 students in class as follows   →  11, 9, 13, 18, 20, 18, 42, 41, 13,

5. In the throw of die, what is the probability of getting a number greater than 6  →  0

6. What is the total number of outcomes, when a coin is tossed →  2