NCERT Class 11 Chemistry Chapter 13 Hydrocarbons Multiple Choice Questions

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Multiple Choice Questions

Question 1. Which one of the following alkenes produces a tertiary alcohol on acid-catalyzed hydration

  1. CH3—CH—CH=CH2
  2. CH3—CH=CH—CH3
  3. (CH3)2C=CH2
  4. CH3-CH=CH

Answer: 3. (CH3)2C=CH2

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Tert Butyl Alcohol

Question 2. Only which one of the following compounds is obtained when excess of Cl2 is passed through boiling toluene

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Boiling Tolene Options

Answer: 4

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Boiling And Excess

Question 3. The Friedel-Crafts reaction using MeCl and anhydrous AlCl3 maybe carried out best with—

  1. Benzene
  2. Nitrobenzene
  3. Toluene
  4. Acetophenone

Answer: 3. Toluene

Due to its +1 and hyperconjugative effect, the —CH3 group increases the electron density of the benzene ring. Thus, toluene becomes more susceptible towards electrophilic substitution reactions. So, Friedel-Crafts reaction using MeCl and anhydrous AlCl3 is carried out best with toluene.

Question 4. Baeyer’s reagent is—

  1. Alkaline potassium permanganate
  2. Acidified potassium permanganate
  3. Neutral potassium permanganate
  4. Alkaline potassium manganate

Answer: 1. Alkaline potassium permanganate

Dilute aqueous solution of alkaline potassium permanganate (1-2%) is called Baeyer’s reagent

Question 5. 2-methylpropane monochloririation under photochemical conditions gives—1

  1. 2-chloro-2-methylpropane as major product
  2. (1 : 1) mixture of l-chloro-2-methylpropane and 2-chloro-2-methylpropane
  3. 1-chloro-2-methylpropane as major product
  4. (1:9) mixture of l-chloro-2-methylpropane and 2- chloro-2-methylpropane

Answer: 3. 1-chloro-2-methylpropane as major product

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons 2 Methylpropane And 2 Chloro 2 Methylpropane

The ratio of A and B in the mixture is 5: 9, though 3° H is more active than 1° H, but in this case number of 1°H is 9 times than that of 3°H.

Question 6. Treatment of with  NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Treatment Of DFDNaNH2/liq.NH3 gives—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Treatment Of DFD Options

Answer: 4.

The given reaction proceeds through the formation of the intermediate, NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Via Benzene Mechanism via the benzyne mechanism

Question 7. The best method for the preparation of 2,2-dimethylbutane is via the reaction of—

  1. Me3CBr and MeCH2Br in Na/ ether
  2. (Me3C)2CuLi and MeCH2Br
  3. (MeCH2)2CuLi and Me3CBr
  4. Me3CMgI and MeCH2I

Answer: 2. (Me3C)2CuLi and MeCH2Br

Corey-House synthesis is the best method for preparing 2,2-dimethylbutane. The corresponding chemical reaction is given as

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Corresponding Of Chemical Reaction

Question 8. The reaction of benzene with Me3CCOCl in the presence of anhydrous AlCl3 gives

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Reaction Of Benzene

Answer: 2

In this electrophilic substitution, removal of CO from the electrophile, acylium ion (Me3CC+=O) results in a more stable tertiary butyl carbocation Me3C+). Thus, C6H5CMe3 is formed as the product.

Question 9. An optically active compound having molecular formula C8H16 on ozonolysis gives acetone (CH3COCH3) as one of the products. The structure of the compound is—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Structure Of Compounds

Answer: 2

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Structure Of Compounds Answer

Question 10. The reagents to carry out the following conversion are—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Reagents To Carry Out Of The Following

Answer: 4

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Tautomerisation

Question 11.  NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Correct Method  Identify the correct method for the synthesis of the compound shown above from the following alternatives—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Alternatives Compounds

Answer: 2

NCERT Solutions For Class 11 Chemistry Chapter 13 HydrocarbonsIdentify The Correct Method For Synthesis

Question 12. 1,4-dimethylbenzene on heating with anhydrous AlCl3 and HCl produces—

  1. 1,2-dimethylbenzene
  2. 1,3-dimethylbenzene
  3. 1,2,3-trimethylbenzene
  4. Ethylbenzene

Answer: 21,3-dimethylbenzene

When 1,4-dimethylbenzene is heated with anhydrous AlCl3 in the presence of HCl it undergoes isomerization to

Question 13. NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Major Product Of The Above Reaction The major product of the above reaction is—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Major Product Of The Above Reaction Options

Answer: 3

The major product in the given reaction can be determined by the following reaction mechanism

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Detremoned By The Following Reaction

Question 14. NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons XSequence Of The Reaction Identify’X’ in the following sequence of reactions—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons X Sequence Of The Reaction Options

Answer: 2

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The X In The Sequence Answer

Question 15. The major products obtained on ozonolysis of 2,3-dimethyl-1-butene followed by reduction with Zn and HO are—

  1. Methanoic acid and 2-methyl-2-butanone
  2. Methanal and 3-methyl-2-butanone
  3. Methanal and 2,2-dimethyl-3-butanone
  4. Methanoic acid and 2-methyl-3-butanone

Answer: 2. Methanal and 3-methyl-2-butanone

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Methanal 3 Methyl 2 Butanone

Question 16. Which one of the following compounds is not aromatic—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Aromatic Compounds

Answer: 2

Cyclooctatetraene is a tub-shaped compound and thus it is non-aromatic.

Question 17. An alkene on ozonolysis produces only one dicarbonyl compound. The alkene is—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Alkene On Ozonolysis Only One Dicarbonyl Compounds

Answer: 2

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Ozonolysis Produces Is

Question 18. The major product(s) obtained from the following reaction of1 mol of hexadeuteriobenzene is/are—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Hexadeuteribenzene

Answer: 1

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Hexadeuteriobenzene Answer

Question 19. The isomerization of 1-butyne to 2-butyne can be achieved by treatment with—

  1. Hydrochloric acid
  2. Ammoniacal silver nitrate
  3. Ammoniacal cuprous chloride
  4. Ethanolic potassium hydroxide

Answer: 4. Ethanolic potassium hydroxide

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Isomerisation Of 1 Butyne

Question 20. The major product(s) obtained in the following reaction is (are)—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Obtained In The Following Reaction

Answer: 1 and 4

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Major Product Obtained Of Enantiomer

Question 21. The number of possible organobromine compounds which can be obtained in the allylic bromination of 1- butene with N-bromo succinamide is—

  1. 1
  2. 2
  3. 3
  4. 4

Answer: 4. 4

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Number Of Organobromine Compounds

Question 22.

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Species

Species 1, 2, 3, and 4 respectively are—

  1. Ethene, ethyne, ethanal, ethane
  2. Ethane, ethyne, ethanal, ethene
  3. Ethene, ethyne, ethanal, ethanol
  4. Ehyne, ethane, ethene, ethanal

Answer: 1. Ethene, ethyne, ethanal, ethane

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Species Of Answer

Question 23. The number of alkenes that can produce 2-butanol by the successive treatment of

1. B2H6 in tetrahydrofuran solvent and

2. Alkaline H2O2solution is

  1. 1
  2. 2
  3. 3
  4. 4

Answer: 1. 1

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Number Of Alkenes Can Be Produce 2 Butanol

Question 24. CH3C=CMgBr can be prepared by the reaction of—

  1. CH3 —C≡C—Br withMgBr2
  2. CH3C≡CH with MgBr2
  3. CH3C≡CH with KBr and Mg metal
  4. HCH3C≡CH with CHgMgBr

Answer: 4. HCH3C≡CH with CHgMgBr

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Acidic Hydrogen

Question 25. Formaldehyde is one of the products obtained on ozonolysis of a compound. The presence of which of the following groups is proved by this observation—

  1. Vinyl group
  2. Isopropyl group CH3
  3. Acetylenic triple bond
  4. Two ethylenic double bonds

Answer: 1. In ozonolysis, the vinyl group is converted into HCHO

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Ozonolysis Vinyl Group Is Converted Into HCHO

Question 26. Which one of the following converts 2-hexyne into 2-hexene—

  1. Li/NH3
  2. Pd/BaSO4
  3. LiAlH4
  4. Pt/H2

Answer: 1. Li/NH3

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons 2 hexyne Form Of 2 Hexane

Question 27. The major organic compound formed by the reaction of 1,1,1-trichloroethane with silver powder is—

  1. 2-butene
  2. Ethene
  3. Acetylene
  4. 2-butyne

Answer: 4. 2-butyne

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Major Organic Compounds

Question 28. In the reaction, NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Reaction Of Product C the product C is—

  1. Acetyl chloride
  2. Acetylene
  3. Acetaldehyde
  4. Ethylene

Answer: 4.  Ethylene

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Product Of C Answers

Question 29.  Which compound would give 5-keto-2-methyl hexanal OH upon ozonolysis?

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Which Compound Would Gives 5 Keto 2 Methyl Hexanal

Answer: 4

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Which Compound Give 5 Keto 2 Methyl Hexanal Answer

Question 30. The product (A) of the reaction given below CH3 is—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Product X Of The Reaction

Answer: 1

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The product X Of The Reaction Answer

Question 31. The reaction of propene with HOCI(Cl3 + H2O) proceeds through the intermediate—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Propene

Answer: 1

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Reaction Of Propane With Proceeds Throug The Intermediate

Question 32. 2-chloro-2-methyl pentane in methanol yields on— reaction with sodium

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Sodium Methoxide In Methanol Yields

  1. Both 1 and 3
  2. Only 2
  3. Both 1 and 2
  4. All of these

Answer: 4. All of these

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Low Yield And High Yield

Question 33. 3-methylpent-2-ene reacts with HBr in the presence of peroxide to yield an additional compound. How many three-dimensional isomers are possible for this addition compound— 

  1. 2
  2. 4
  3. 6
  4. 0

Answer: 2. 4

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons 3 Methylpent 2 ene

The resulting compound consists of two different asymmetric centers (shown by asterisks). Thus the number of three-dimensional isomers = 22 = 4

Question 34. Which one of the following compounds undergoes mononitration to yield a considerable amount of m product—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Mono Nitration To Yield Considerable

Answer: 1

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons During The Nitarion Of Aniline

During tire nitration of aniline, —NH2 group gets protonated and form an anilinium ion ( —NH3). The + —NH3 group is deactivating and meta-orienting. Thus during the mono nitration of aniline, a significant amount of meta-product is obtained

Question 35. The major product of the following reaction is

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Major Product Of The Following Reaction

Answer: 4

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Due To Neopentyl Type Of Structure

Due to the neopentyl type of structure, it cannot undergo SN2 reaction

Question 36.  The trans-alkenes are formed by the reduction of alkynes with—

  1. Na/liq. NH3
  2. H2/Pd-C,BaSO4
  3. Sn/HCl
  4. NaBH4

Answer: 1. Na/liq. NH3

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Alkyne

Question 37.  NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Major Products Of 1 And 3 RespectivelyThe major products 1 and 3 are respectively

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Major Products Of 1 And 3 Respectively.

Answer: 3

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Major Product Of 1 And 3 Respectively

Question 38. In the following reaction

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Major Products Of Minor Product

Answer: 3.

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons In The Following Reactions Answer

Question 39. Which of the following reagents is used to distinguish between 1-butyne and 2-butyne—

  1. HCl
  2. OH
  3. Br
  4. NaNH2

Answer: 4. NaNH2

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Between 1 Butyne And 2 Butyne

Question 40. Which one of the following compounds is most reactive towards electrophilic-nitration reaction—

  1. Toluene
  2. Benzene
  3. Benzoic acid
  4. nitrobenzene

Answer: 1. Toluene

Due to +1 and the hyperconjugation effect of —CH3 group, toluene is the most reactive toward electrophilic nitration reaction

Question 41. Which of the following compounds will not undergo Friedel-Crafts reaction easily

  1. Toluene
  2. Cumene
  3. xylene
  4. Nitrobenzene

Answer: 4. Nitrobenzene

Groups like nitro ( —NO2) withdraw electrons from the benzene ring and deactivate the ring to such an extent that it cannot be attacked by the relatively weak electrophile. So, nitrobenzene does not undergo FriedelCraft reaction

Question 42. The radical  NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Aromaticis aromatic because it has—

  1. 6p-orbitals and 7 unpaired electrons
  2. 6p-orbitals and 6 unpaired electrons
  3. 7p- orbitals and 6 unpaired electrons
  4. 7p-orbitals and 7 impaired electrons

Answer: 3. 7p- orbitals and 6 unpaired electrons

The given free radical is aromatic because it contains a benzene ring having 6n -electrons which remain delocalised. The seventh odd electron does not play any role in determining the aromaticity of the
free radical.

Question 43. Some meta-directing substituents in aromatic substitution are given. Which is most deactivating— 

  1. COOH
  2. —NO2
  3. —C=N
  4. —SO3H

Answer: 2. —NO2

Due to -I and -R effect, —NOa is a highly deactivating and —CN, —SO3H and moderately deactivating meta-orienting group

Question 44. Nitrobenzene, on reaction with cone. HNO3/H2SO4 at 80-100°C forms one of the following products—

  1. 1,4-dinitrobenzene
  2. 1,2,4-trinitrobenzene
  3. 1,2-dinitrobenzene
  4. 1,3-dinitrobenzene

Answer: 4. 1,3-dinitrobenzene

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Nitrobenzene And 1 And 3 Dinitrobenzene

Question 45. Identify the sequence of reactions NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Z Sequence Of Reactions

  1. CH3(CH2)3-O-CH2CH3
  2. (CH3)2CH—O—CH2CH3
  3. CH3(CH2)4—O-CH3
  4. CH3CH2-CH(CH3)-O-CH2CH3

Answer: 1. CH3(CH2)3-O-CH2CH3

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Identify Z Reaction Equation Answers

Question 46. Which of the following organic compounds has the same hybridization as its combustion product (CO2) —

  1. Ethane
  2. Ethyne
  3. Ethene
  4. Ethanolic

Answer: 2. Ethyne

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons C Atom In Both Ethyne And Carbondioxide

C-atom in both ethyne and CO2 is sp -sp-hybridized

Question 47. The oxidation of benzene by V2O5 in the presence of air produces—

  1. Benzoic anhydride
  2. Maleic anhydride
  3. Benzoic acid
  4. Benzaldehyde

Answer: 2. Maleic anhydride

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Maleic Anhydride

Question 48. Which of the following is not the product of dehydration of

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Dehydration

Answer: 2

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Between Does Not Form Because The Intermediate Carbocation  does not form because the intermediate carbonation NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Highly Stable i.e is highly stable, so it does not undergo rearrangement

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Undergo Rearrangement

Question 49. In the reaction with HCI, an alkane reacts by Markownikoff’s rule, to give a product 1-chloro-1 methylcyclohexane. The possible alkane is—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Possible Alkene

Answer: 3

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Methylcyclohexane Reactions

Question 50. Because of the absence of torsional strain, staggered conformation is more stable than eclipsed conformation.

  1. The correct statement regarding the comparison of staggered and eclipsed conformations of ethane is— the staggered conformation of etha HPgi*less stable than eclipsed conformation because staggered hasÿirsional strain
  2. The eclipsed conformation of ethane is more stable than staggered conformation because eclipsed conformation has no torsional strain
  3. The eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has torsional strain
  4. The staggered conformation of ethane is more stable than eclipsed conformation because staggered conformation has no torsional strain

Answer:  4. The staggered conformation of ethane is more stable than eclipsed conformation because staggered conformation has no torsional strain

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Less Stable And More Stabel

Question 51. Consider the nitration of benzene using a mixed cone. H2SO4 and HNO3.If a large amount of KH2SO4 is added to the mixture, the rate of nitration will be—

  1. Faster
  2. Slower
  3. Unchanged
  4. Doubled

Answer: 2. Slower

⇒ \(\mathrm{HNO}_3+2 \mathrm{H}_2 \mathrm{SO}_4 \rightleftharpoons \mathrm{H}_3 \stackrel{\oplus}{\mathrm{O}}+\stackrel{\oplus}{\mathrm{N}} \mathrm{O}_2+2 \mathrm{HSO}_4^{\ominus}\)

Addition of KHSO4 increases the concentration of

H2SO4 and due to the common ion effect, the production of

NO+2 decreases which slows down the nitration process

Question 52. In the reaction NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons In The Reaction X And Y

X and 7 are—

  1. X = 1 -butyne; Y- 3 -hexyne
  2. X = 2 -butyne; Y = 3 -hexyne
  3. X = 2 -butyne; 7=2 -hexyne
  4. X = 1 -butyne; 7=2 -hexyne

Answer: 1.  X = 1 -butyne; Y- 3 -hexyne

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons In The Reactions Answers

Question 53. Which of the following compounds shall not produce propene by reaction with HBr followed by elimination or direct only elimination reaction—

1. CH3 CH2CH2OH

2. CH3 CH2CH2Br

3. CH2=C=O

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Elimination Reaction Option 4

Answer: 2. CH3 CH2CH2Br

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons HBR Elimination

Question 54. In the given reactionNCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons In The Reaction P the product P is

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons In The Reaction P.

Answer: 2

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons In Given The Reaction Product P Is

Question 55. The compound that will react most readily with gaseous bromine has the formula—

  1. C2H2
  2. C4H10
  3. C2H4
  4. C3H6

Answer: 4. C3H6

The reaction undergoes via a radical pathway. Among the given alkenes, propene can form the most stable radical intermediate and thus it undergoes the reaction faster than other alkenes.

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons More Stable Radical

Question 56. Which one is the correct order of acidity—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Correct Order Of Acidity

Answer: 1.

For a C-atom in the hybridised state, acidic character increases with increase of the s-character. Again the presence alkyl group reduces the acidic property due to its +1 effect. Hence the order of acidity of the given compounds:

Question 57. Nitration of aniline in a strong acidic medium also gives  -m-nitroaniline because

  1. In acidic (strong) medium aniline is present as an anilinium ion
  2. Inspite of substituents nitro group always goes to only m -position
  3. In absence of substituents nitro group always goes to m -m-position
  4. In electrophilic substitution reactions amino group is meta-directive

Answer: 1. In acidic (strong) medium aniline is present as an anilinium ion

Question 58. The compound C7H8 undergoes the following reactions  NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Compound Undergoes The Following Reactions The Product ‘C

 is___________

  1. p -bromotoluene
  2. m – bromotoluene
  3. 3-bromo-2,4,6-trichlorotoluene
  4. o -bromotoluene

Answer: 2. m – bromotoluene

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Compound Undergoes The Following Reaction

Question 59. Hydrocarbon (d) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to a gaseous hydrocarbon containing less than four carbon atoms. A is—

  1. CH4
  2. HC≡CH
  3. CH3 – CH3
  4. CH2 = CH2

Answer: 1.CH4

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Hydrocarbon Reacts With Bromine

Question 60. Identify the major products P, Q and R in the following sequence of reactions  NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Major Product Of PQR

 

Answer: 1

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Sequence Reaction PQR.

Question 61. When trans-butene is reacted with Br2 the product formed is

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Trans Butene Is Reacted With Bromide

3. Meso-compounds

4. Both 2 And 3

Answer: 4. Both 2 And 3

With trans-but-2-ene, the product of Br2 addition is Br optically inactive due to the formation of symmetric me-so-compounds

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Symmetric Meso Compounds

Question 62. What is ‘A’in the following—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons What Is Following Reaction

Answer: 3

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons What Is A Following Reaction

Question 63.  Which of the following aromatic—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Aromatic Following

Answer: 4

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Planar 6 Pi Electrons

Any planar cyclic system containing (4n + 2)n electrons and having a single cyclic n -electron cloud encompassing all the carbon atoms in the ring is aromatic

Question 64. Which of the following alkenes will give the same product by any method out of hydration, hydroboration-oxidation and oxymercuration-demarcation—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Oxymercuration Demercuration

Answer: 2. CH3CH=CHCH3

CH3CH=CHCH3 is symmetrical and gives the same product by any of the given methods adopted

Question 65. Which of the following species is not aromatic

  1. Benzene
  2. Cyclooctatetraenyl dianion
  3. Tropyliumion
  4. Cyclopentadienyl cation

Answer: 4.  Cyclopentadienyl cation

On applying the Huckel’s rule, [(4n + 2)n -electron] system

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Huckels Rule

Question 66. What will be compound A in the following reaction—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons What Will Be Compound A In the Following Reaction

Answer: 1.

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Compound Of The Following Reaction Answer

Question 67.NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Identify Major And Minor. Identify X 

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Identify Major And Minor

Answer: 3

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Strong Electron Releasing

Strong electron releasing group ( — OCH3) generally predominates over the deactivating group ( —NO2). Thus, o – and p – products will be formed. Due to steric hindrance ortho-product will be formed in lesser amount than para-product

Question 68. Which Brof the following compounds is aromatic in nature—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Aromatic In Nature

Answer: 1,3 and 4

1: Due to the presence of (4n + 2)πe in; it follows Huckel’s rule and therefore,it is aromatic. Due to the presence of an extra lone pair of electrons in , total electron comes out to be 4πe . Thus, it is antiaromatic.

3: In although it is cyclic and has conjugated Huckel’s (4n + 2)πe rule is not followed here and also ring is notplanar. Hence,it is non-aromatic.

4: It has 6πe in conjugation but not in the ring, hence it is non-aromatic

Question 69. In the given reaction  NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Given In the Reaction A‘A’is________

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons In The Reaction A

Answer: 2

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons In The Given Reaction Electrophilic Addition ReactionAnswer

Question 70. What is the decreasing order of boiling points for the following compounds

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Boiling Points

  1. 1> 2 > 3
  2. 2 >3> 1
  3. 1 > 3 > 2
  4. 3 > 2 > 1

Answer: 1.1> 2 > 3

Question 71. The correct order of decreasing boiling points of the following hydrocarbons is—

1. n-butane

2. 2-methylbutane

3. n-pentane

4. 2,2- dimethylpropane

  1. (1) > (2) > (3) > (4)
  2. (2) > (3) > (4) > (1)
  3. (4) > (3) > (2) > (1)
  4. (3) > (2) > (4) > (1)

Answer: 4. (3) > (2) > (4) > (1)

Question 72. Addition of HBr with 1-butane (CH3CH2CH=CH2) forms a mixture consisting of 1,2 and 3

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Addition Of HBr

In the mixture—  

  1. 1 and 2 exist as major products while 3 as minor product
  2. 2 exists as major product and 3 as minor products
  3. 2 exists as a minor product whileI and 3 as major products
  4. 1 and II exist as minor products while 3 as majorproduct

Answer:  1and 2 exist as major products while 3 as minor product

Question 73. Which of the following alkenes does not exhibit geometrical isomerism—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Alkenes Does Not Exhibit Geometrical

  1. 1 and 2 exist as major products while 3 as minor product
  2. Exists as major product while and 3 as minor products
  3. 2 exists as minor products while 3 as major products
  4. 1 and 2 exist as minor products while 3 a major product

Answer:  4. 1 and 2 exist as minor products while 3 as major product

Question 74. When a mixture of concentrated aqueous solutions of sodium salts of two monocarboxylic acids is electrolysed, a mixture of ethane, propane and butane is obtained at the anode. The two acids are

CH2COOH, CH3CH2COOH

  1. CH3COOH, HCOOH
  2. CH3CH2COOH,CH3CH2CH2COOH
  3. (CH3)2CHCOOH, CHCOOH

Answer:  1. CH2COOH, CH3CH2COOH

Question 75.  The products formed when CH3I, CH3CHO and CH3CH2COOH are respectively reduced by HI in presence of red phosphorus are—

  1. CH3CH3, CH3CH3, CH3CH2CH3
  2. CH4, CH3CH3, CH3CH2CH3
  3. CH3CH2CH3, CH4, CH3CH3
  4. CH4, CH3CH2CH3, CH3CH2CH2CH3

Answer: 2. CH4, CH3CH3, CH3CH2CH3

Question 76. The decreasing order of boiling points of isomeric pentanes is—

  1. n-pentane > isopentane > neopentane
  2. Isopentane > n-pentane > neopentane
  3. Neopentane > isopentane > n-pentane
  4. n-pentane > neopentane > isopentane

Answer: 1. n-pentane > isopentane > neopentane

Question 77. The reactivity of different types of hydrogen during halogenation of alkanes follows the order—

  1. 2°H > 1°H > 3°H
  2. 1°H >2°H > 3°H
  3. 2°H > 3°H > 1°H
  4. 3°H > 2°H > 1°H

Answer: 4. 3°H > 2°H > 1°H

Question 78. The correct IUPAC name of the monochord derivative that forms as the major product during chlorination of 3-ethyl pentane is—

  1. 1-chloro-3-ethyl pentane
  2. 2-chloro-3-ethyl pentane
  3. 3-chloro-3-ethyl pentane
  4. 3-ethyl-3-chloroethane

Answer:  3. 3-chloro-3-ethyl pentane

Question 79. Which of the following symmetrical alkanes is not prepared by Wurtz reaction—

  1. Ethane
  2. Butane
  3. 2,2,3,3-tetramethyl butane
  4. 2,3-dimethylbutane

Answer: 3. 2,2,3,3-tetramethyl butane

Question 80. The octane numbers of 2,2,4-trimethylpentane isooctane) and n-pentane are respectively—

  1. 50,50
  2. 100,0
  3. 0,100
  4. 50,0

Answer: 2. 2. 100,0

Question 81. The increasing order of octane numberis

  1. n-alkane < branched alkane < cycloalkane < aromatic hydrocarbon
  2. Aromatic hydrocarbon < cycloalkane < branched alkane < n-alkane
  3. Cycloalkane < branched alkane < aromatic hydrocarbon < n-alkane
  4. Aromatic hydrocarbon < cycloalkane < n-alkane < branched alkane

Answer: 1. n-alkane < branched alkane < cycloalkane < aromatic hydrocarbon

Question 82. The amount of oxygen (in mole) required for the combustion of1 mol hydrocarbon (CÿHÿ,) is—

  1. \(\left(x+\frac{y}{4}\right)\)
  2. \(\left(y+\frac{x}{4}\right)\)
  3. (x+y)
  4. \(\left(x+\frac{y}{2}\right)\)

Answer: 1. \(\left(x+\frac{y}{4}\right)\)

Question 83. Which of the following compounds on reacting with Grignard reagent (RMgX) does not form an alkane—

  1. CH3C=CH
  2. CH3CH2OCH2CH
  3. C2H5OH
  4. H2O

Answer:  2. CH3CH2OCH2CH

Question 84. The change in the hybridisation state of carbon in ethane duringits combustion is—

  1. sp³→sp
  2. sp²→sp³
  3. sp→sp³
  4. sp→sp²

Answer: 1. sp³→sp

Question 85. The intermediate formed during chlorination of methane in diffused sunlight is

  1. \(\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_3\)
  2. :CH2
  3. CH3
  4. :CH3

Answer:   3. CH3

Question 86. The product formed when 2 equivalent ofmetallic sodium reacts with l-bromo-3-chlorocyclobutane in ether medium is

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Equivalent Metallic Sodium

Answer: 4

Question 87. Which of the following compounds are not formed when a mixture of ethyl iodide and n-propyl iodide is subjected to Wurtz reaction—

  1. Butane
  2. Propane
  3. Pentane
  4. Hexane

Answer: 2. Propane

Question 88. In Kolbe’s electrolytic process which of the following compounds does not lead to the formation of an alkane—

  1. CH3COONa
  2. CH3CH2COONa
  3. HCOONa
  4. CH3CH2CH2COOK

Answer: 3. HCOONa

Question 89. —I + Zn +I —R—>R —R + Znl2; The reaction is—

  1. Frankland reaction
  2. Grignard reaction
  3. Wurtzreaction
  4. Corey-House synthesis

Answer: 1. Frankland reaction

Question 90. Which of the following statements is not true—

  1. Alkanes are non-polar compounds
  2. Alkanes are insoluble in polar solvents like water
  3. Among isomeric alkanes, n-alkane has the lowest boiling point
  4. Higher alkanes (> C17) are hard like wax

Answer: 3. Among isomeric alkanes, n-alkane has the lowest boiling point

Question 91. The reagent which is not used in the preparation of propene from 1-bromopropane is

  1. Water/KOH
  2. Ethanol/ C2H5ONa+
  3. Ethanol/KOH
  4. Tert-butylalcohol/(CH3)3COK+

Answer: 1. Water/KOH

Question 92. The reducing agent which is not used to prepare RCH=CHR from RC=CR is—

  1. Na/liq.NH3
  2. H2/Lindlar’s catalyst
  3. B2H6 /tetrahydrofuran
  4. H2/PtorPd

Answer: 4. H2/PtorPd

Question 93. Decreasing order of stability of the given carbanions is—

1. CH3—C≡C:

2. H —C=C:

3. CH3—:CH2

  1. 1 > 2 > 3
  2. 2 > 1> 3
  3. 3 > 2 > 1
  4. 3 > 1 > 2

Answer: 2. 2 > 1> 3

Question 94. Baeyer’s reagent which is used in the Baeyer’s test for detecting ethylenic unsaturation is—

  1. An acidic solution of potassium permanganate
  2. A dilute alkaline solution of potassium permanganate
  3. An aqueous solution of bromine
  4. A solution ofbrominein acetic acid

Answer: 2. A dilute alkaline solution of potassium permanganate

Question 95. Which of the following compounds on ozonolysis forms C02 along with other products—

  1. CH2=C=CHCH3
  2. CH3CH=CH—CH=CH2
  3. CH3CH=CH—CH=CH2
  4. CH3CH=CH—CH=CH2

Answer: 1. CH2=C=CHCH3

Question 96. Which of the following compounds on ozonolysis forms a carbonyl compound

  1. CH3CH=CH2
  2. (CH3)2C=CHCH3
  3. (CH3)2C=C(CH3)2
  4. CH2=CH —CH=CH2

Answer:  3. (CH3)2C=C(CH3)2

Question 97. Alkene which forms CH3COCH2CH2CH2CH2COCH3 on ozonolysis is

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Alkene Which Form Ozonolysis

Answer:  4.

Question 98. An alkene, on ozonolysis forms HCHO, CH3COCHO and CH3CHO. The alkene is—

  1. CH2=C(CH3)—CH=CHCH3
  2. CH2=C(CH3) —CH2 —CH=CH2
  3.  CH3—CH=CH—CH=CHCH3
  4. CH3—CH=CH—CH2—CH=CH2

Answer: 1. CH2=C(CH3)—CH=CHCH3

Question 99. CH3COCOCH3, CH3COCHO and OHC—CHO are formed due to the ozonolysis of o-xylene. The ratio in which the compounds are formed—

  1. 3:2:1
  2. 2:3:1
  3. 1:2:3
  4. 3:1:2

Answer: 3. 1:2:3

Question 100. Which of the following reactions occurs following Markownikoff’s rule

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Accordance With Markowinkoffs Rule

Answer:  4

Question 101. For which of the following reaction, Markownikoff’s rule is applicable—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Following Reaction Markownikoffs Rule Applicable

Answer:  3

Question 102. The intermediate which is formed in the first step of the reaction between CH3CH=CH2 and HBr is a

  1. Carbanion
  2. Carbocation
  3. Free radical
  4. Carbene

Answer: 2.

Question 103. Among all the HX compounds, only HBr reacts with CH3CH=CH2 in the presence ofperoxide according to antiMarkownikoff’s rule. This is because, in case of HBr, the third and fourth steps

1. CH3—CH=CH2 + Br→CH3CHCH2Br and

2. CH3CHCH2Br + H —Br→CH3CH2CH2Br + Br )

  1. The third step is exothermic while the fourth step is endothermic
  2. Both the steps are exothermic
  3. The third step is endothermic while the fourth step is exothermic and the fourth steps
  4. Both the steps are endothermic

Answer: 2. Both the steps are exothermic

Question 104. Which of the given compounds on reacting with HBr forms the same product in the presence and absence of peroxide—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Absence Of Peroxide

Answer: 3

Question 105. The order of acidity of ethyne (1), ethane (2) and ethene (3) is

  1.  2 >1 >3
  2. 1 >3 >2
  3. 1 >2 >3
  4. 2 >3 >1

Answer: 3. 1 >2 >3

Question 106. The compound which does not form a red precipitate on reacting with ammoniacal cuprous chloride solution is—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Ammonical Cuprous Chloride

Answer: 2

Question 107. The reagent that cannot be used to distinguish between ethylene and acetylene is—

  1. Ammoniacal cuprous chloride
  2. Br2/H2O
  3. Dil. H2SO4/Hg2+
  4. Ammoniacal silvernitrate solution

Answer:  2. Br2/H2O

Question 108. Two compounds, when subjected to ozonolysis separately,  CH3COCH2CH3(2mol) NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons 1 Mole The compounds are— each form and

  1. Enantiomers
  2. Diastereomers
  3. Metamers
  4. Tautomers

Answer:  1. Enantiomers

Question 109. The compound Y in the given reaction is –

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Compound Y In The Given Reaction

Answer: 1

 

Question 120. The addition of HBr occurs most readily for—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Addition Of HBr Occcurs

Answer: 4.

Question 121.  NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons In The Reaction A In this reaction a is

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons In The Reaction A Options

Answer: 1.

Question 122. Which of the following compounds undergoes hydrolysis to form propyne-

  1. Al4C3
  2. Mg2C3
  3. B4C
  4. La4C3

Answer: 2.Mg2C3

Question 123. Hydration of alkenes (except ethylene) in presence of acid produce—

  1. 1° alcohols
  2. 2° or 3° alcohols
  3. Mixture of1° and 2° alcohols
  4. Mixture of 2° and 3° alcohols

Answer: 2. 2° or 3° alcohols

Question 124. Cyclohexanone NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Cyclohexanone  react with witting reagents (Ph3P—CHR) to form—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Cyclohexanone Reacts With Wittig Reagent

Answer: 3

Question 125. When ethylene gas is passed through an aqueous solution of NaCl and Br2 the compound whose formation is not possible is—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Ethylene Gas Is Options

Answer: 3

Question 126. Hydrocarbons Here X Is Here , X is

  1. Cyclobutane
  2. Cyclopropane
  3. Cyclopentane
  4. Cyclohexane

Answer: 2. Cyclopropane

Question 127. Which of the following alkynes cannot be converted into a terminal alkyne when heated with NaNH2/ paraffin—

  1. CHC3=CCH3
  2. CH3CH2C=CCH2CH3
  3. CH3CH2CH2C=CCH2CH3
  4. (CH3)2CHC=CCH(CH3)2

Answer: 4. (CH3)2CHC=CCH(CH3)2

Question 128. Correct order of decreasing reactivity of the given com¬ pounds towards electrophilic substitution reaction is –

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Towards Elecytrophilic Substitution Reaction

  1. 3 > 1 > 2 > 4
  2. 4 > 1 > 2 > 3
  3. 1 > 2 > 3 > 4
  4. 2 > 1 > 3 > 4

Answer: 1. 3 > 1 > 2 > 4

Question 129. Number of monochloride derivatives possible for diphenylmethane NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Diphenylmethane

  1. 4
  2. 8
  3. 7
  4. 18

Answer: 1. 4

Question 130. The compound which is formed in excess when Cl2 reacts with toluene in presence of FeCl3 is—

  1. Benzyl chloride
  2. o – and p -chlorotoluene
  3. m -chlorotoluene
  4. Benzoyl chloride

Answer: 2. o – and p -chlorotoluene

Question 131. The major product obtained when NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Major Product Obtainedundergoes monobromination(with Fe Br)is 

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Undergoes Monobromination

Answer: 2

Question 132. Polysubstitution occurs for which of the following reactions—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Ploysubstitution Following Reactions

Answer: 2

Question 133.  NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons X Compound Is compound X is________________

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons X Compound Options

Answer: 2.

Question 134. The compound which is most reactive in case of electrophilic attack is-

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Electrophilic Attack

Answer: 1

Question 135. Benzene does not form additional compound because—

  1. It has ring structure
  2. Its double bond is verystrong
  3. It has 6 equivalent h-atoms
  4. Its aromatic stability is lost

Answer: 4. Its aromatic stability is lost

Question 136. In strong acidic and alkaline medium, p-aminophenol exists in (X) and (Y) forms respectively

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Strong Acidic And Alkaline Medium

Thus, in acidic and alkaline medium, electrophilic substitution occurs at-

  1. a,c
  2. a,d
  3. b,c
  4. b,d

Answer: 1. a,c

Question 137. In electrophilic substitution reaction of benzene—

  1. The first step is exothermic but the second step is endothermic
  2. The first step is endothermic but the second step is exothermic
  3. Both the steps are exothermic
  4. Both the steps are endothermic

Answer: 2.  The first step is endothermic but the second step is exothermic

Question 138. The method suitable for converting benzene into propylbenzene is 

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Converting Benzene Into Propyl Benzene

Answer: 3

Question 139. An aromatic compound of molecular formula C8H10 reacts with a mixture of concentrated HNO3 and concentrated H2SO4 to form a mononitro compound. The structural formula of C8H10 is

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Mononitro Compound

Answer: 4

Question 140. Nitrobenzene is prepared from benzene by using conc. HNO3 and cone. H2SO4 . In the nitrating mixture, nitric acid acts as a/an—

  1. Base
  2. Acid
  3. Reducing agent
  4. Catalyst

Answer: 1.  Base

Question 141. On passing excess Cl2(g) through boiling toluene, the only compound that forms is—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Boilinhg Toluene

Answer: 4

Question 142. Which of the given participates in Friedel-Crafts reaction—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Participates In Friedel Crafts Reaction

Answer: 4

Question 143. In which of the following compounds the ring on the left side undergoes electrophilic substitution reaction—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Left Side Undergoes Electrophilic Substitution

Answer: 4

Question 144. The increasing order of the rate of nitration reaction of the following compounds is- 

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Nitration Reaction

  1. 2 < 3 < 1 < 4 < 5
  2. 4 < 5 < 1 = 3 < 2
  3. 4 < 1 = 3 < 5 < 2
  4. 1 < 3 < 2 < 5 < 4

Answer: 2.  4 < 5 < 1 = 3 < 2

Question 145. The major product formed in the following reaction is- NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Major Product Formed In The Following Reaction

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Major Product Formed In The Following Reaction Options

Answer: 4.

Question 146. NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons The Compound X is

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons X Compound Is Options

Answer: 2

Question 147. The acidity of which of the following compounds is quite high compared to the rest of the given compounds—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Quite High Compared To The Rest Options

Answer: 3

Question 148. Bromination takes place most rapidly in—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Bromination Takes Place Most Rapidly

Answer: 2

Question 149.  NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons X And Y Are Reactions

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons X And Y Compound Options

Answer: 1

 

Question 158. Benezene when subjected to ozonolysis (03 followed by Zn/H2O ) forms—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Benzene When Ozonolysis

Answer: 1

Question 159. BHC is a/an—

  1. Fertiliser
  2. Insecticide
  3. Explosive
  4. Solvent

Answer: 2.  Insecticide

Question 160. (CH3)3CMgCl reacts with D2O to form—

  1. (CH3)3CD
  2. (CH3)3OD
  3. (CD3)3CD
  4. (CD3)3OD

Answer: 1.  (CH3)3CD

Question 161. Which two compounds undergo ozonolysis to produce CH3CHO, CH3COCHO and HCHO —

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Two Compounds Undergo Ozonolysis To Produce

Answer: 2, 3

Question 162. Among the following oxidation reactions of methane, which two are controlled oxidation reactions —

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Controlled Oxidation Reactions

Answer: 3,4

Question 163. Which of the following alkenes undergo ozonolysis to form a mixture of two ketones—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons A Mixture Of Two Ketones

Answer: 3,4

Question 164. Which of the following compounds form the same product with HBr in presence and absence of peroxide—

  1. Cyclohexene
  2. But-2-ene
  3. Hex-3-ene
  4. 1-methylcyclohexene

Answer: 1,2,3

Question 165. The compounds which react with dilute H2SO4 in the presence of HgS04 to form methyl ketone are—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Methyl Ketone

Answer: 2,3,4

Question 166. The compounds which only form glyoxal when subjected to ozonolysis are—

  1. Ethene
  2. Benzene
  3. Toluene
  4. Ethyne

Answer: 2,4

Question 167. In which of the following compounds, nitration take place at the para-position—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Nitration Take Place Para Position

Answer: 2,4

Question 168. Which of the following groups are deactivating but ortho-J para-orienting—

  1. —Cl
  2. —CH=CH—COOH
  3. —N=O
  4. -CF3

Answer: 1,2,3

Question 169. Which two of the following groups are used to block a definite position in the benzene ring-

  1. -SO3H
  2. — CH3
  3. — CF3
  4. —CMe3

Answer: 1,4

Question 170. Which of the following reactions do not occur—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Which Of The Following Reactions Do Not Occur

Answer: 1,2

question 171. Which of the following reactions do not take place easily in the benzene ring—

  1. Polyadenylation
  2. Polynitration
  3. Poly sulphonation
  4. Polyalkylation

Answer: 1,2,3

Question 172. Polybrominated takes place in which of the given cases—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Polybromination Takes Place

Answer: 2,3

Question 173. In which of the following reactions, toluene is obtained— When methanol reacts with PhMgBr

  1. Na-salt of o -toluic acid is heated with sodalime
  2. p-cresol is distilled in presence of Zn dust
  3. Benzyl alcohol is heated in the presence of red
  4. Phosphorous and concentrated HI

Answer: 2,3,4

Question 174. In which of the reactions, ferf-butylbenzene is formed—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Tert Butylbenzene

Answer: 1,3,4

Question 175. Which on ozonolysis forms a mixture of two ketones—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Ozonolysis Form A Mixture Of Two Ketones

Answer: 1,3,4

Question 176. Which of the following compounds undergo chlorination to produce a type of monochloroalkane—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Type Of Monochloroalkane

Answer: 1,2,4

Question 177. Which undergoes nitration reaction faster than benzene-

  1. C6H5CH3
  2. C6H5NHCOCH3
  3. C6H5COOH
  4. C6H5CHO

Answer: 1,2

Question 178. Which undergoes nitration reaction slower than benzene—

  1. C6H5CH=CHCOOH
  2. C6H5CH=CH-NO2
  3. C6H5CMe3
  4. C6H5OCH3

Answer: 1,2

Question 179. Which of the following σ -complexes are more stable than the cr -complex of benzene—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Sigma Complex Of Benzene

Answer: 1,4

Question 180. Which of the following compounds has 10 isomers—

  1. CI2C6H3NH2
  2. CH3C6H4NO2
  3. BrClC6H3CHO
  4. O2NC6H3BrCH3

Answer: 3,4

Question 181. The compounds which get oxidised by alkaline KMn04 to form benzoic acid are —

  1. Toluene
  2. Ethylbenzene
  3. Tert-butyl benzene
  4. Benzyl chloride

Answer: 1,2,4

Question 182. Which of the following can be used to distinguish between ethylene and acetylene—

  1. Bromine water
  2. Ammoniacal Cu2Cl2
  3. Ammoniacal AgNO solution
  4. Dilute alkaline kmnO4 solution

Answer: 2,3

Question 183. In which two compounds, homolytic cleavage of the C—Ha bond takes place most readily—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Homolytic Cleavage

Answer: 1,2

Question 184. The compounds which do not participate in Friedel Crafts reaction are —

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Do Not Participate In Friedel Crafts Reactions

Answer: 1,2,4

Question 185. Which of the following cannot be used as an alkylating reagent in Friedel-Crafts reaction—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Alkylating Reagent In Friedel Crafts Reaction

Answer: 2,4

Question 186. Which of the following facts are correct

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Which OF The Following Facts Are Correct

Answer: 1,3

 

Question 190. Markownikoff’s rule is applicable for which of the following reactions—

NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons Markownikoffs Rule Is Applicable Following Reactions

Answer: 1,2

 

Leave a Comment