NCERT Solutions For Class 11 Chemistry Chapter 11 Some P Block Elements Multiple Choice Questions
Question 1. Which of the following metals has the largest abundance in the earth’s crust
- Aluminium
- Magnesium
- Calcium
- Sodium
Answer: 1. Aluminium
Question 2. For BCl3, AlCl3 and GaCl3 the increasing order of ionic character is
- BCl3 < AlCl3< GaCl3
- GaCl3 < AlCl3 < BCl3
- BCl3< GaCl3< AlCl3
- AlCl3 < BCl3 < GaCl3
Answer: 3. BCl3< GaCl3< AlCl3
The ionic character of a compound depends on the polarising power of the cation present in it. The more the polarising power of the cation, the less the ionic character of the compound containing the cation. The polarising power of the cations B+3, Al+3 and Ga+3 is Al+3 < Ga+3 < B+3. Hence, the increasing order of ionic character will be BCl3 < GaCl3< AlCl3
Question 3. In borax, the number of B- O- B link and B- OH bonds present are respectively
- Five and four
- Four and five
- Three and four
- Five and five
Answer: 1. Five and four
Question 4. In diborane, the number of electrons that account for bonding in the bridges is
- Six
- Two
- Eight
- Four
Answer: 4. Four
Two bridging bonds are present in diborane. In the bridges, each H-atom is bonded to two B-atoms by sharing of only one pair of electrons i.e., 3c-2e bonds. Thus, the total number ofelectrons for two bridges is four.
Question 5. The main reason that SiCl4 is easily hydrolysed as compared to CCl4 is that
- SiCl bond is weaker than C — Cl bond
- SiCl4 can form hydrogen bonds
- SiCl4 is covalent
- Si can extend its coordination number beyond four
Answer: 4. Si can extend its coordination number beyond four
In SiCl4 , Si has a vacant d -orbital. Therefore, it can expand its coordination through coordinate bonding to get hydrolysed
Question 6. Which ofthe following ions cannot be formed by boron
- BF3-6
- BH–4
- B(OH)–4
- BO–2
Answer: 1. BF3-6
Boron cannot expand its covalency beyond four due to the unavailability of π-orbitals. Thus it cannot form BF3-6.
Question 7. Which of the following exists as covalent crystals in the solid state
- Phosphorus
- Iodine
- Silicon
- Sulphuric
Answer: 3. Silicon
Silicon exists as covalent crystals in a solid state
Question 8. Which of the following are Lewis acids
- PH6 and SiCl4
- BCl3 and AlCl3
- PH3 and BC
- AlCl3 and SiCl4
Answer: 2. BCl3 and AlCl3
Both BCl3 and AlCl3 have incomplete octets around the central atom. Thus they can act as Lewis acids.
Question 9. Which of the following oxides is amphoteric
- SnO2
- CaO
- SiO2
- CO2
Answer: 1. SnO2
SnO2 reacts with both acids as well as with bases. Hence, it is an amphoteric oxide
SnO2 + 4HCl→SnCl2+ 2H2O
SnO2 + 2NaOH→Na2SnO3+ H2O
Question 10. Which of the following statements is incorrect—
- Pure sodium dissolves in liquid ammonia to give a blue solution
- NaOH reacts with glass to give sodium silicate
- Aluminium reacts with excess NaOH to give Al(OH)3
- NaHCO3 on heating gives Na2CO3
Answer: 3. Aluminium reacts with excess NaOH to give Al(OH)3
Aluminium reacts with NaOH to form sodium metaaluminate (NaAlO2).
Question 11. Name the two types ofthe structure of silicate in which one oxygen atom of [SiO4]4- is shared
- Linear chain silicate
- Sheet silicate
- Borosilicate
- Three-dimensional
Answer: 3. Pyrosilicate
Question 12. Which of these is least likely to act as a Lewis base
- BF3
- PF
- CO
- F
Answer: 1. BF3
BF3 is a Lewis acid
Question 13. Which ofthe following is electron-deficient
- (BH3)2
- PH3c
- (CH3)2
- (SiH3)2
Answer: 1. (BH3)2
Boron hydrides are electron-deficient compounds
Question 14. Number of carbon atoms per unit cell of diamond unit cell
- 1
- 4
- 8
- 6
Answer: 2. 4
Diamond exists as a face-centred cubic unit cell. Thus, at the centre of each face one atom is present i.e., ½ × 6 = 3 atoms. Also, ½ × 8 = 1 atom is present at the comers. Hence, the total no. of atoms per unit cell = 3 +1 = 4 atoms.
Question 15. . Which of these is not a monomer for a high molecular mass silicone polymer
- PhSiCl3
- MeSiCl3
- Me2SiCl2
- Me3SiCl
Answer: 4. Me3SiCl
Polymerisation involves the repeating of monomeric units. If Me3 SiCl units are joined, then a dimer is formed rather than a polymer.
Question 16. Which ofthe following structures is similar to graphite
- B2H6
- BN
- B
- B4C
Answer: 2. BN
Question 17. The basic structural unit of silicate is
- SiO2-4
- SiO–
- SiO4-4
- SiO2-3
Answer: 3.SiO4-4
Question 18. The stability of the +1 oxidation state among Al, Ga, In and Tl increases in the sequence
- Ga<In<Al<Tl
- Al < Ga < In < Tl
- Tl < In < Ga < A1
- In <T1 < Ga < Al
Answer: 2. Al < Ga < In < Tl
Question 19. AlF3 is soluble In HF only In the presence of HF. It is due to the formation of
- K3(AlF6)
- AlH3
- K3(AlF3H)
- K3(AlF3H3)
Answer: 1. K3(AlF6)
The maximum coordination number shown by AF63- is 6 and thus it can form A1F|- ion.
Question 20. Boric acid is an acid because its molecule
- Gives up a proton
- Accepts OH from water releasing a proton
- Combines with a proton from the water molecule
- Contains replaceable H -ion
Answer: 2. Accepts OH from water releasing a proton
H3BO3 is a Lewis acid and it takes up OH ion giving up H ion in the solution.
Question 21. It is because of the inability of ns² electrons of the valence shell to participate in bonding that
- Sn2+ is oxidising while Pb4+ is reducing
- Sn2+ and Pb4+ are both oxidising and reducing
- Sn4+ is reducing while Pb4+ is oxidising
- Sn2+ is reducing while Pb4+ is oxidising
Answer: 4. Sn2+ is reducing while Pb4+ is oxidising
The inert pair effect increases down the group. Hence Sn2+ acts as a reducing agent whereas Pb4+ is an oxidising agent
Question 22. Which one of die following elements is unable to form MF63- ion
- In
- Ga
- B
- Al
Answer: 3. B
Boron does not have any vacant orbital. Therefore it cannot expand its coordination more than 4. Thus it is unable to form a compound ofthe type MF63-
Question 23. The correct order of atomic radii in group 13 elements is
- B < Ga < Al < In < Tl
- B < Al < In < Ga < Tl
- B < Ga < Al < Tl < In
- B < Al < Ga < In < Tl
Answer: 1. B < Ga < Al < In < Tl
Due to the weak screening effect of d -d-orbital, the atomic radius of Ga is less than that of AI.
Question 24. The wrong statement about fullerene is
- It has 5-membered carbon ring
- It has 6-membered carbon ring
- It has sp² hybridisation
- It has 5-membered rings more than 6-membered rings
Answer: 4. It has 5-membered rings more than 6-membered rings
Fullerene consists of 12 five-membered rings and 20 six-membered rings. So it has five-membered rings less than six-membered rings
Question 25. Iodine oxidises sodium borohydride to give
- B2H6
- Sodium hydride
- HI
- I–3
Answer: 1. B2H6
The oxidation of sodium borohydride with iodine in diglyme gives diborane.
Question 26. Which material is used as a neutron moderator
- Graphite
- Boron
- Cadmium
- Uranium
Answer: 1. Graphite
Neutron moderators slow down the speed of neutrons by collisions. They do not absorb neutrons. For
Example: Water and graphite
Question 27. For silicon which is not correct
- It is a type of silicate
- It is hydrophilic
- It is thermally unstable
- The repeating unit is R2SiO
Answer: 3. Silicon is hydrophobic
Question 28. Which ofthe following is not sp² -hybridised
- Graphite
- Graphene
- Fullerene
- Dry ice
Answer: 4. Dry ice
Solid CO2 is dry ice in which carbon atom undergoes sp -hybridization
Question 29. The pair of amphoteric hydroxides is
- Be(OH)2, Al(OH)3
- Al(OH)3,LiOH
- B(OH)3,Be(OH)2
- Be(OH)2, Mg(OH)2
Answer: 1. Be(OH)2, Al(OH)3
Al and Be show similar properties due to their diagonal relationship
Question 30. Which ofthe following reactions do not take place
BF3 + F–→BF4– …………..(1)
BF3 + 3F–→BF43-…………..(2)
AlF3 + 3F–→AlF3-6 ………….(3)
- Only 1
- Only 2
- Only 3
- Only 1 and 3
Answer: 2. Only 2
BF3 forms complex halides of the type BF–4 in which the B atom has coordination number 4. It cannot extend its coordination number beyond 4 due to the unavailability of d -d-orbitals in its configuration. Hence, BFg ion (sp³d³ hybridisation) is not formed. On the other hand, AI can extend its coordination number beyond 4 due to the availability of d -d-orbitals in its configuration.
Question 31. Select the correct options from the following
- Graphene is an atomic layer of graphite.
- Graphene is an atomic layer composed of sp² – hybridised carbon.
- Chemical bonds in graphite are similar in strength to that of diamond.
- All of these.
Answer: 4. All of these.
Question 32. Among the following substituted silanes, the one which will give rise to cross-linked silicone polymer on hydrolysis is
- R3SiCl
- R3SiCl
- RSiCl3
- R3SiCl
Answer: 3. RSiCl3
Question 33. Hydride of boron occurs as B2H6 but B2C16 does not exist This is because
- pπ-dπ back bonding is possible in B2H6 but not in R2SiCl2
- Boron and hydrogen have almost equal values of electronegativity
- Boron and chlorine have almost equal atomic sizes
- Small hydrogen atoms can easily fit in between boron atoms but large chlorine atoms do not.
Answer: 1. pπ-dπ back bonding is possible in B2H6 but not in R2SiCl2
Question 34. Which of the given compounds does not react with dilute HC1 at high temperature
- SnSO4
- PbSO4
- BiOCl
- CdSO4
Answer: 2. PbSO4
PbSO4 belongs to group I so, it is insoluble in HCl. Acidity increases with the addition of ethylene glycol. It also exhibits a 3D arrangement due to hydrogen bonding.
Question 35. Boric acid is a weak acid, but in the presence of which ofthe following compounds, it behaves as a stronger acid
- Glycerol
- Acetic acid
- Ethanol
- Ethylene
Answer: 1. Glycerol
Question 36. The structure of diborane (B2H6) contains—
- Four 2c-2e bonds and four 3c-2e bonds
- Two 2c-2e bonds and two 3c-3e bonds
- Two 2c-2e bonds and four 3c-2e bonds
- Four 2c-2e bonds and two 3c-2e bonds
Answer: 4. Four 2c-2e bonds and two 3c-2e bonds
Question 37. Which of the following elements is used in high-temperature thermometry
- Al
- Ga
- Hg
- In
Answer: 2. Ga
Question 38. An important ingredient of Pyrex glass is—
- Zn
- Pb
- B
- Fe
Answer: 3. B
Question 39. Which ofthe following is the purest allotrope of carbon
- Diamond
- Fullerene
- Graphite
- Charcoal
Answer: 2. Fullerene
Question 40. The number of isomers possible for disubstituted borazine, B3N3H4X2 is-
- 3
- 4
- 5
- 6
Answer: 2. 4
Question 41. Pentaborane-9 (B5H9) is an example of
- Arachno-borane
- Pseudo-borane
- Nido-borane
- Close-borane
Answer: 1. Arachno-borane
Question 42. So when reacts with A forms B. A & B respectively are
- HF, H2SiF4
- HF, H2SiF6
- HCl, H2SiCl6
- HI, H2SiI6
Answer: 2. HF, H2SiF6
Question 43. Boric acid is a
- Monobasic and weak Lewis acid
- Monobasic and weak Bronsted acid
- Monobasic and strong Lewis acid
- Tribasic and weak Bronsted acid
Answer: 1. Monobasic and weak Lewis acid
Question 44. Which ofthe following does not exist in a free state
- BF3
- BCl3
- BBr3
- BH3
Answer: 4. BH3
Question 45. The correct order of decreasing Lewis acid character is
- BCl3 > AlCl3> GaCl3 > InCl3
- AlCl3 > BCl3> InCl3> GaCl3
- AlCl3 > GaCl3> BCl3 > InCl3
- InCl3 > GaCl3 > AlCl3 > BCl3
Answer: 1. BCl3 > AlCl3> GaCl3 > InCl3
Question 46. Which of the following is present in the chain structure of silicate
- (Si2O2-5)n
- (Si2O2-3)n
- Si2O4-4
- Si2O6-7
Answer: 2. (Si2O2-3)n
Question 47. A metal, M forms chlorides in +2 and +4 oxidation states. Which ofthe following statements about these chlorides is correct
- MCl2 is more volatile than MCl4
- MCl2 is more ionic than MCl4
- MCl2 is more soluble in any. ethanol than MCl4
- MCl2 is more easily hydrolysed than MCl4
Answer: 2. MCl2 is more ionic than MCl4
Question 48. The number of O-atoms that are shared per Si04 tetrahedra in silicate anion of beryl is
- 4
- 3
- 2
- 1
Answer: 3. 2
Question 49. Which of the following on hydrolysis produces crosslinked silicone polymer
- R4Si
- RSiCl3
- R2SiCl2
- R3SiCl
Answer: 2. RSiCl3
Question 50. The antidote of poisoning caused by CO is
- Carborundum
- Carbogen
- Carbonic acid
- Pure oxygen
Answer: 2. Carbogen
Question 51. Carbon suboxide in reaction with water produces
- Oxalic acid
- Formic acid
- Lactic acid
- Malonic acid
Answer: 4. Malonic acid
Question 52. The volume of which liquid metal increases on solidification
- Ga
- Al
- Zn
- Cu
Answer: 1. Ga
Question 53. Which ofthe following reacts only with alkali
- Question B2O3
- Al2O3
- Ga2O3
- ln2O3
Answer: 1. B2O3
Question 54. Which is the strongest Lewis acid
- BF3
- BCl3
- BBr3
- BI3
Answer: 4. BI3
Question 55. The atomic radius of Ga is slightly less than that of Al. The reason is
- Weaker shielding effect of s-electrons of Ga
- Stronger shielding effect of s -electrons of Ga
- Weaker shielding effect of d -electrons of Ga
- Stronger shielding effect of d -electrons of Ga
Answer: 3. Weaker shielding effect of d -electrons of Ga
Question 56. Carbon does not form complexes, because
- Vacant d -d-orbitals are absent in it
- It is not a metal
- Its atomic radius is small
- It is neutral
Answer: 1. Vacant d -d-orbitals are absent in it
Question 57. Supercritical CO2 is used as
- Dry ice
- Fire extinguisher
- A solvent for the extraction of organic compounds from natural sources
- The inert solvent in various reactions
Answer: 3. A solvent for the extraction of organic compounds from natural sources
Question 58. The stability of the +1 oxidation state increases in the sequence
- Al < Ga < In < Tl
- Tl<In<Ga<Al
- In < Tl < Ga < Al
- Ga<In<Al<Tl
Answer: 1. Al < Ga < In < Tl
Question 59. Which ofthe following is acidic
- B2O3
- Al2O33
- Ga2O3
- ln2O3
Answer: 1. B2O3
Question 60. The correct order of first ionisation enthalpy for Gr-13 elements is
- B > Al > Ga > In > Tl
- B < Al < Ga < In < Tl
- B < l> Ga < In > Tl
- B > Al < Ga > In < Tl
Answer: 4. B > Al < Ga > In < Tl
Question 61. Which of the following elements is not likely to be the central atom in MF3-6
- B
- Al
- Ga
- In
Answer: 1. B
Question 62. The tendency of catenation in Gr-14 elements follows the order
- C > Si > Ge > Sn
- C>Si > Ge ≈ Sn
- Si > C > Sn > Ge
- Ge > Sn > Si > C
Answer: 2. C>Si > Ge ≈Sn
Question 63. The repeating structural unit in silicone is
Answer: 2.
Question 64. Which of the following allotropic forms of carbon is isomorphous with crystalline silicon
- Graphite
- Coal
- Coke
- Diamond
Answer: 4. Diamond
Question 65. The shape and hybridisation of the B-atom of BH– 4 is
- Pyramidal, sp³
- Octahedral, sp³ d²
- Tetrahedral, sp³
- None of these
Answer: 3. Tetrahedral, sp³
Question 66. Germanium is transparent in—
- Visible light
- Infrared region
- Ultraviolet region
- Ultraviolet region
Answer: 2. Infrared region
Question 67. The chain length of silicone polymer can be controlled by adding
- MeSiCl
- Me2SiCl2
- Me3SiCl
- Me4Si
Answer: 3. Me3SiCl
Question 68. Higher B—F (in BF3) bond dissociation energy as compared to that of C— F (in CF4 ) is due to
- Stronger cr-bond between B and F in BF3 as compared to that between C and F in CF4
- Significant pn-pn interaction between B and F in
- BF3 whereas there is no possibility of such interaction between C and F in CF4
- Lower degree of pn-pn interaction between B and F in BF3 than that between C and F in CF4 smaller size of B -atom as compared to that of C -atom
Answer: 2. Significant pn-pn interaction between B and F in
Question 69. The reaction of diborane with ammonia initially gives
- B2H6.NH3
- B2H6-3NH3
- Borazol
- [BH2(NH3)2]+[BH4]–
Answer: 4. [BH2(NH3)2]+[BH4]–
Question 70.
X, y, Z and their respective colours are
- X = Cu(BO2)2 (blue) , Y = CuBO2 (colourless) , Z= Cu (red)
- 2. CuBO2(blue) , y =Cu(BO2)2 (colourless),Z = Cu (Black)
- X = Cu(BO2)2 (red) , Y = CuBO2 (blue) Z = (red)
- X = Cu (red) , Y = Cu(BO2)2 (blue) , Z = CuBO (colourless)
Answer: 1. X = Cu(BO2)2 (blue) , Y = CuBO2 (colourless) , Z= Cu (red)
Question 71. The correct formula for borax is—
- Na2[B4O4OH)3].9H2O
- Na2[B4O5(OH)4].8H2O
- Na2[B4O6(OH)5].7H2O
- Na2[B4O7(OH)6]-6H2O
Answer: 2. Na2[B4O5(OH)4].8H2O
Question 72. Which ofthe following statements is correct
- Sn (2) and Pb (4) salts are used as oxidants
- Sn (2) and Pb (4) salts are used as reductants
- Sn (2) salts are used as oxidants and Pb (4) salts are used as reductants
- Sn (2) salts are used as reductants and Pb (4) salts are used as oxidants
Answer: 4. Sn (2) salts are used as reductants and Pb (4) salts are used as oxidants
Question 73. SiCl4 gets readily hydrolysed but CC14 does not, because
- Si can expand its octet but C does not
- The ionisation enthalpy of C is greater than that of Si
- C forms both double and triple bonds
- The electronegativity of C is greater than that of Si
Answer: 1. Ionisation enthalpy of C is greater than that of Si
Question 74. PbCl4 exists but PbBr4 and Pbl4 do not, because
- Chlorine is a most electronegative element
- Bromine and iodine are larger
- Bromine and iodine cannot oxidise Pb to Pb4+
- Bromine & iodine are stronger oxidants than chlorine
Answer: 3. Bromine and iodine cannot oxidise Pb to Pb4+
Question 75. Which of the following resembles CO in terms of physical properties
- O2
- Cl2
- N2
- F2
Answer: 3. N2
Question 76. Which ofthe following statements is incorrect
- Most of the silicones are water repellents
- Silicones get dissociated at high temperature
- Silicones do not get oxidised in air at high temperature
- Silicones are good thermal and electrical insulators
Answer: 2. Silicones get dissociated at high temperature
Question 77. Wollastonite is a
- Three-dimensional silicate
- Chain silicate
- Sheet silicate
- Cyclic silicate
Answer: 4. Cyclic silicate
Question 78. B(OH)3 + NaOH ⇌ NaBO2 + Na[B(OH)4] + H2O; The above reaction be made to proceed in the forward direction by
- Addition of diol
- Addition of borax
- Addition of KHF2
- Addition ofNaHPO4
Answer: 1. Addition of diol
Question 79. Which ofthe following is correct
- Al(OH)3 is more acidic than B(OH)3
- B(OH)3 is basic but Al(OH)3 is amphoteric in nature
- B(OH)3 is acidic but Al(OH)3 is amphoteric in nature
- Both B(OH)3 and Al(OH)3 are amphoteric
Answer: 3. B(OH)3 is acidic but Al(OH)3 is amphoteric in nature
Question 80. Which ofthe following is correct
- B2H6-2NH3 is known as inorganic benzene
- Boric acid is a protonic acid
- Be exhibits coordination number = 6
- BeCl3 and AlCl3 have bridged chlorine structures in the solid phase
Answer: 4. BeCl3 and AlCl3 have bridged chlorine structures in the solid phase
Question 81. B cannot form B3+ ion, because
- Formation of B3+ ion requires a greater amount of energy and this cannot be obtained from lattice energy or hydration energy.
- B is a non-metal
- B do not possess any vacant d -orbitals
- B possess the highest melting point among its group members
Answer: 1. Formation of B3+ ion requires a greater amount of energy and this cannot be obtained from lattice energy or hydration energy
Question 82. Which of the following has the minimum heat of dissociation
- (CH3)3N :-→BF3
- (CH3)3N :-→B(CH3)2F3
- (CH3)3N :→B(CH3)3
- (CH3)3N :→B(CH3)F2
Answer: 3. (CH3)3N :→B(CH3)3
Question 83. The correct statement concerning CO is
- It combines with H2O to give carbonic acid
- It reacts with haemoglobin
- It acts only as a reducing agent
- It cannot form adducts
Answer: 2. It reacts with haemoglobin
Question 84. Foamite mixture consists of
- Al(SO)3 + NaHCO
- Al2(SO4)3 + Na2CO3
- Fe2(SO4)3 + Na2CO3
- CuSO4 + NaHCO3
Answer: 1. Al2(SO4)3 + Na2CO3
Question 85. In which of the following compounds, the 3c-2e bond is present
- AI2(CH3)6
- In (C6H5)3
- B2H6
- AlCl
Answer: 1 and 2
Question 86. Which ofthe following oxides do not get reduced by CO
- ZnO
- Fe2O
- CaO
- Na2O
Answer: 1 and 3
Question 87. Which ofthe following is not isostructural with CO2
- SnCl2
- HgCl2
- SCl2
- Znl2
Answer: 2 and 4
Question 88. C(OH4) is unstable but Si(OH)4 is stable. Possible reasons are
- C—O bond energy is low
- C—O bond energy is high
- Si—O bond energy is low
- Si
Answer: 1 and 4
Bond energy is high
Question 89. Which ofthe following statements are correct
- Fullerenes have dangling bonds
- Fullerenes are cage-like molecules
- Graphite is thermodynamically the most stable allotrope of carbon
- Graphite is the purest allotrope of carbon
Answer: 2 and 3
Question 90. Boron trifluoride (BF3) is
- An electron-deficient compound
- A Lewis acid
- An ionic compound
- Used as rocket fuel
Answer: 1 and 2
Question 91. Compounds which readily undergo hydrolysis are
- AlCl3
- CCl4
- SiCl4
- PbCl3
Answer: 1, 3 and 4
Question 92. Which of the following compounds undergo disproportionation in aqueous solution
- TlCl3
- GaCl
- InCl
- TlCl
Answer: 2 and 3
Question 93. Me3SiCl is used during polymerisation of organoisilicones because
- The chain length of organosilicon polymers can be controlled by adding Me3SiCl.
- Me3SiCl blocks the end terminal of the silicone polymer
- Me3SiCl improves the quality and yield of the polymer
- Me3SiCl acts as a catalyst during polymerisation
Answer: 1 and 2
Question 94. Which of the following acids, on dehydration, produce oxides of carbon
- Succinic acid
- Propanoic acid
- Malonic acid
- Formic acid
Answer: 3 and 4
Question 95. Which of the following are basic
- B2O3
- Tl2O
- ln2O3
- Al2O3
Answer: 2 and 3
Question 96. The linear shape of C02 is due to
- sp³ -hybridisation of C
- sp -hybridisation of C
- pπ-pπ bonding between C and O
- sp² -hybridisation of C
Answer: 2 and 3
Question 97. Which metallic salts exhibit the same colouration both in oxidising and reducing flame in the borax-bead test
- Fe
- Mn
- Co
- Cr
Answer: 3 and 4
Question 98. Which of the following two acidic substances react to give an alkaline solution
- H2B4O7
- H3BO3
- HF
- KHF2
Answer: 2 and 4
Question 99. Which of the following are the ingredients of baking powder
- NaOH
- Tartaric acid
- Formic acid
- Potassium hydrogen tartrate
Answer: 2 and 4
Question 100. Which ofthe following are sheet silicates
- Diopside
- Kaolinite
- Talc
- Beryl
Answer: 2 and 3
Question 101. Identify the correct resonating structures
- O -C ≡ O
- O= C=O
- O ≡ C-O+
- –O – C≡O+
Answer: 2 and 4
Question 102. Which of the following species are not known
- [SiCl6]2-
- [CF6]2-
- [PbCl6]2-
- [SiF6]2-
Answer: 2 and 3
Question 103. Which of the following are correct concerning Gr-14 elements
- Stability of dihalides: CX2 > SiX2 > GeX2 > SnX2
- The tendency to form pn-pn multiple bonds increases down the group
- The tendency of catenation decreases down the group
- Each of them forms oxide ofthe type MO2
Answer: 2, 3 and 4